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9.8.1: Closure of a part of the tidal basin

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    截屏2021-12-08 下午10.07.11.png
    Figure 9.35: Effect of closure of part of the basin on the channel volume \(V_c\) and the volume of the outer delta \(V_{\text{od}}\) (crosses: initial situation, solid dots: immediately after closure, open dots: new equilibrium). From Eqs. and it can be seen that a change in the prism has a larger effect on the equilibrium channel volume than on the equilibrium volume of the outer delta. Closure 1 (left) has a smaller \(\Delta V_c\) than closure 2 (right). The reduction of the tidal prism \(\Delta P\) is the same for both closures. Corresponding numbers are found in Table 9.6.

    The closure of a part of the tidal basin will result in a reduction of the channel volume, \(V_c\), and of the tidal prism \(P\). The basins will adapt to the new situation, see Fig. 9.35. In this example we will neglect the role of the flats and assume that they are already more or less in equilibrium immediately after the closure.

    The two lines in Fig. 9.35 represent the relationship of the channel volume and the tidal prism with \(C_V\) is \(65 \times 10^{-6} m^{-3/2}\) and the relationship of the sand volume of the outer delta and the tidal prism with \(C_{\text{od}}\) is \(65.7 \times 10^{-4}\ m^{-3/2}\). Assume an equilibrium situation with tidal prism \(P\) and corresponding channel volume \(V_c\) and sand volume of the outer delta \(V_{\text{od}}\). At a certain moment in time, a part of the tidal basin is closed off, which results in a reduction of the channel volume \(\Delta V_c\) and a reduction of the tidal prism \(\Delta P\). A new equilibrium will arise at the equilibrium lines for tidal prism \(P - \Delta P\). This means that the channel volume is \(a\ m^3\) too big and the sand volume of the outer delta is \(b\ m^3\) too big. The sand of the outer delta is available for the adaptation of the channels (to an amount of \(b\ m^3\)). The rest, if \(a - b > 0\), has to be supplied from outside (resulting in erosion of the downdrift coast). Closure 1 (Fig. 9.35, left) and closure 2 (Fig. 9.35, right) differ in the magnitude of \(\Delta V_c\). As a consequence \(a - b > 0\) for closure 1 and \(a - b < 0\) closure 2 (see Table 9.6).

    Table 9.6: Values corresponding to closures and accretion of Figs. 9.35 and 9.36. All variables in \(10^6 m^3\).
      closure 1 closure 2 accretion
    Prism before 600 600 300
    Prism after 300 300 225
    \(\Delta V_c\) 300 470 0
    \(V_{c, \text{before}}\) 955 955 338
    \(V_{c, \text{after}}\) 338 338 219
    \(a\) 318 148 118
    \(V_{od, \text{before}}\) 412 412 176
    \(V_{od, \text{after}}\) 176 176 123
    \(b\) 236 236 52
    \(a- b\) 82 -88 66

    An example of the above situation is the closure of the Lauwerszee in 1969 (see Fig. 9.2) as described in Wang et al. (2009) and reprinted in App. E. Due to the decrease of the tidal basin area, the tidal prism and thereby the magnitude of the flow velocity decreased significantly. The tidal asymmetry changed such that it became more flood-dominant favouring sediment input. The effect of the closure therefore was a sediment deficit that needed to be supplied from outside. Since the closure, the basin has been accumulating sediment and the ebb-tidal delta has been eroding. The sedimentation in the basin and the erosion of the ebb-tidal delta are more or less in balance. As a consequence the closure has not caused erosion of the adjacent coasts.

    This page titled 9.8.1: Closure of a part of the tidal basin is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Judith Bosboom & Marcel J.F. Stive (TU Delft Open) via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.